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0=9x^2-5x-210
We move all terms to the left:
0-(9x^2-5x-210)=0
We add all the numbers together, and all the variables
-(9x^2-5x-210)=0
We get rid of parentheses
-9x^2+5x+210=0
a = -9; b = 5; c = +210;
Δ = b2-4ac
Δ = 52-4·(-9)·210
Δ = 7585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{7585}}{2*-9}=\frac{-5-\sqrt{7585}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{7585}}{2*-9}=\frac{-5+\sqrt{7585}}{-18} $
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